Vermont, Wisconsin
From Wikipedia, the free encyclopedia
| Vermont, Wisconsin | |
|---|---|
| — Town — | |
 |
|
| Coordinates: 43°4′57″N 89°46′26″W / 43.0825°N 89.77389°WCoordinates: 43°4′57″N 89°46′26″W / 43.0825°N 89.77389°W | |
| Country | United States |
| State | Wisconsin |
| County | Dane |
| Area | |
| • Total | 35.8 sq mi (92.6 km2) |
| • Land | 35.8 sq mi (92.6 km2) |
| • Water | 0.0 sq mi (0.0 km2) |
| Elevation[1] | 945 ft (288 m) |
| Population (2000) | |
| • Total | 839 |
| • Density | 23.5/sq mi (9.1/km2) |
| Time zone | Central (CST) (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
| FIPS code | 55-82525[2] |
| GNIS feature ID | 1729677[1] |
Vermont is a town of Dane County in the state of Wisconsin in the United States. 839 people were living in Vermont as of 2000. Vermont has a total area of 35.8 square miles, according to the United States Census Bureau.
References [change]
- ↑ 1.0 1.1 "US Board on Geographic Names". United States Geological Survey. 2007-10-25. http://geonames.usgs.gov. Retrieved 2008-01-31.
- ↑ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.
Other websites [change]
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