Garden Grove, Iowa
Garden Grove is a city in Decatur County, in Iowa in the United States. There were 174 people at the time of the 2020 census.[1]
Garden Grove | |
|---|---|
 | |
 | |
| Coordinates: 40°49′35″N 93°36′28″W | |
| Country | United States |
| State | Iowa |
| County | Decatur County |
| Area | |
| • Total | 0.69 sq mi (1.79 km2) |
| • Land | 0.69 sq mi (1.79 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 1,112 ft (339 m) |
| Population | |
| • Total | 174 |
| • Density | 257.40/sq mi (99.38/km2) |
| Area code | 641 |
Geography[change | change source]
Garden Grove is located at 40°49′35″N 93°36′28″W (40.826479, -93.607732).
History[change | change source]
A strong EF2 tornado hit the town on March 5, 2022.
Demographics[change | change source]
2010 census[change | change source]
At the 2010 census there were 211 people in 49 families, in 78 houses in the city.
The medium age was 38.1 years.
2000 census[change | change source]
At the 2000 census there were 250 people in 96 houses, in 64 families.
References[change | change source]
- ↑ 1.0 1.1 "Garden Grove city, Iowa". United States Census Bureau. Retrieved November 6, 2023.
- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.