Jefferson, Ohio
Jefferson, Ohio | |
|---|---|
 | |
 Location of Jefferson, Ohio | |
 Location of Jefferson in Ashtabula County | |
| Coordinates: 41°44′14″N 80°46′19″W / 41.73722°N 80.77194°WCoordinates: 41°44′14″N 80°46′19″W / 41.73722°N 80.77194°W | |
| Country | United States |
| State | Ohio |
| County | Ashtabula |
| Government | |
| • Mayor | Judy Maloney |
| Area | |
| • Total | 2.52 sq mi (6.53 km2) |
| • Land | 2.52 sq mi (6.53 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 958 ft (292 m) |
| Population (2010) | |
| • Total | 3,120 |
| • Estimate (2018[2]) | 2,994 |
| • Density | 1,238.1/sq mi (478.0/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 44047 |
| Area code(s) | 440 |
| FIPS code | 39-38500[3] |
| GNIS feature ID | 1042061 |
| Website | http://www.jeffersonohio.us/ |
Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,120 at the 2010 census. It is the county seat of Ashtabula County.[4]
References[change | change source]
- ↑ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
- ↑ "Population and Housing Unit Estimates". Retrieved June 30, 2019.
- ↑ "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
- ↑ "Find a County". National Association of Counties. Archived from the original on 2011-05-31. Retrieved 2011-06-07.
Municipalities and communities of Ashtabula County, Ohio, United States | ||
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| Cities |  | |
| Villages | ||
| Townships | ||
| CDPs | ||
| Unincorporated communities | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
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