Pomeroy, Iowa

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City of Pomeroy
City
Location of Pomeroy in the state of Iowa.
Location of Pomeroy in the state of Iowa.
City of Pomeroy is located in Iowa
City of Pomeroy
Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361
Country United States
State Iowa
County Calhoun
Government
 • Mayor David Berger
Area
 • Total 2.0 sq mi (5.3 km2)
 • Land 2.0 sq mi (5.3 km2)
 • Water 0.0 sq mi (0.0 km2)
Elevation 1,240 ft (378 m)
Population (2000)
 • Total 710
 • Density 347.4/sq mi (134.1/km2)
Time zone Central (CST) (UTC-6)
 • Summer (DST) CDT (UTC-5)
Area code(s) 712
FIPS code 19-64065[1]
GNIS feature ID 0460354[2]
Website http://www.downtownpomeroy.com/

Pomeroy is a city in Calhoun County, Iowa, United States. The population of Pomeroy was 710 in 2000.

Pomeroy was hit by a tornado on July 6, 1893, that was estimated to be F5 on the Fujita scale. There was a damage path of around 500 yards (460 m) wide and 55 miles (89 km) long and the tornado destroyed about 80% of the homes in Pomeroy. It killed 71 people and injured 200 others.

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