Petersburg, Indiana

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City of Petersburg
City
Location in Indiana
Coordinates: 38°29′30″N 87°16′49″W / 38.49167°N 87.28028°W / 38.49167; -87.28028Coordinates: 38°29′30″N 87°16′49″W / 38.49167°N 87.28028°W / 38.49167; -87.28028
Country United States
State Indiana
County Pike
Township Washington
Area
 • Total 1.47 sq mi (3.81 km2)
 • Land 1.47 sq mi (3.81 km2)
 • Water 0 sq mi (0 km2)  0%
Elevation 482 ft (147 m)
Population (2010)
 • Total 2,383
 • Estimate (2012[1]) 2,373
 • Density 1,621.1/sq mi (625.9/km2)
Time zone EST (UTC-6)
 • Summer (DST) EDT (UTC-5)
ZIP code 47567
Area code(s) 812
FIPS code 18-59364[2]
GNIS feature ID 0449709[3]

Petersburg, Indiana is a city of Indiana in the United States. It is the county seat of Pike County.

References[change | edit source]