Pomeroy, Iowa

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City of Pomeroy
City
Location of Pomeroy in the state of Iowa.
Pomeroy, Iowa is located in Iowa
City of Pomeroy
Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361
Country United States
State Iowa
County Calhoun
Government
 • Mayor David Berger
Area
 • Total 2.0 sq mi (5.3 km2)
 • Land 2.0 sq mi (5.3 km2)
 • Water 0.0 sq mi (0.0 km2)
Elevation 1,240 ft (378 m)
Population (2000)
 • Total 710
 • Density 347.4/sq mi (134.1/km2)
Time zone Central (CST) (UTC-6)
 • Summer (DST) CDT (UTC-5)
Area code(s) 712
FIPS code 19-64065[1]
GNIS feature ID 0460354[2]

Pomeroy is a city in Calhoun County, Iowa, United States. The population of Pomeroy was 710 in 2000.

Pomeroy was hit by a tornado on July 6, 1893, that was estimated to be F5 on the Fujita scale. There was a damage path of around 500 yards (460 m) wide and 55 miles (89 km) long and the tornado destroyed about 80% of the homes in Pomeroy. It killed 71 people and injured 200 others.

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