Andrew, Iowa

Coordinates: 42°09′15″N 90°35′30″W / 42.154059°N 90.591765°W / 42.154059; -90.591765
From Simple English Wikipedia, the free encyclopedia
Andrew, Iowa
Location of Andrew, Iowa
Location of Andrew, Iowa
Coordinates: 42°09′15″N 90°35′30″W / 42.154059°N 90.591765°W / 42.154059; -90.591765
Country United States
State Iowa
CountyJackson
IncorporatedAugust 4, 1863 [1]
Area
 • Total0.25 sq mi (0.64 km2)
 • Land0.25 sq mi (0.64 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation
883 ft (269 m)
Population
 • Total380
 • Density1,532.26/sq mi (591.69/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP code
52030
Area code563
FIPS code19-02125
GNIS feature ID0454187

Andrew is a city in Iowa in the United States.

References[change | change source]

  1. "List of Incorporated Cities" (PDF). Iowa Secretary of State. Retrieved 24 January 2020.
  2. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  3. "Andrew city, Iowa". United States Census Bureau. Retrieved November 3, 2023.