Albany, Pepin County, Wisconsin
From Wikipedia, the free encyclopedia
| Albany, Wisconsin | |
|---|---|
| — Town — | |
| Location of Albany, Pepin County, Wisconsin | |
| Coordinates: 44°38′6″N 91°42′57″W / 44.635°N 91.71583°WCoordinates: 44°38′6″N 91°42′57″W / 44.635°N 91.71583°W | |
| Country | United States |
| State | Wisconsin |
| County | Pepin |
| Area | |
| • Total | 36.0 sq mi (93.3 km2) |
| • Land | 36.0 sq mi (93.3 km2) |
| • Water | 0.0 sq mi (0.0 km2) |
| Elevation[1] | 1,191 ft (363 m) |
| Population (2000) | |
| • Total | 620 |
| • Density | 17.2/sq mi (6.6/km2) |
| Time zone | Central (CST) (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
| FIPS code | 55-00800[2] |
| GNIS feature ID | 1582667[1] |
Albany is a town in Pepin County, Wisconsin, United States. 620 people lived here as of the year 2000.
References [change]
- ↑ 1.0 1.1 "US Board on Geographic Names". United States Geological Survey. 2007-10-25. http://geonames.usgs.gov. Retrieved 2008-01-31.
- ↑ "American FactFinder". United States Census Bureau. http://factfinder.census.gov. Retrieved 2008-01-31.