1896 United States presidential election

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1896 United States presidential election

← 1892 November 3, 1896 1900 →

All 447 electoral votes of the Electoral College
224 electoral votes needed to win
Turnout79.3%[1] Increase 4.6 pp
  William McKinley by Courtney Art Studio, 1896.jpg William Jennings Bryan 2.jpg
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Alliance People's, Silver
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall (Democratic, Silver)
Thomas E. Watson (Populist)
Electoral vote 271 176
States carried 23 22
Popular vote 7,111,607 6,509,052
Percentage 51.0% 46.7%

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About this image
Presidential election results map. Red shows those won by McKinley/Hobart, blue shows states won by Bryan/Sewall and the Populist ticket of Bryan/Watson. Numbers show the number of electoral votes given to each state.

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election was the 28th presidential election. It happened on Tuesday, November 3, 1896. Former Governor William McKinley, the Republican candidate, defeated Democrat William Jennings Bryan. The 1896 campaign happened during an economic depression called the Panic of 1893. It was a realigning election that ended the old Third Party System and began the Fourth Party System.[2]

References[change | change source]

  1. "Voter Turnout in Presidential Elections". The American Presidency Project. UC Santa Barbara.
  2. Williams (2010)

Other websites[change | change source]