1928 United States presidential election

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1928 United States presidential election

← 1924 November 6, 1928 1932 →

531 members of the Electoral College
266 electoral votes needed to win
Turnout56.9%[1] Increase 8.0 pp
  Herbert Hoover - NARA - 532049.jpg AlfredSmith.jpg
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 444 87
States carried 40 8
Popular vote 21,427,123 15,015,464
Percentage 58.2% 40.8%

ElectoralCollege1928.svg
Presidential election results map. Red denotes states won by Hoover/Curtis, blue denotes those won by Smith/Robinson. Numbers indicate the number of electoral votes allotted to each state.

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

The 36th United States Presidential election occurred on November 6, 1928. The election was won by Herbert Hoover. Incumbent President Calvin Coolidge, who had been president since the death of Warren G. Harding in 1923 and was elected to a full term in 1924, decided not to run for re-election.

Al Smith, the losing candidate who was a Roman Catholic, was the first Catholic nominee for a major party in American history. He faced widespread anti-Catholic opposition. Hoover was, after all, a Protestant since he grew up in a Quaker family. It wasn't until 1960 that a Roman Catholic, John F. Kennedy, was elected.

Candidates[change | change source]

Republican Party[change | change source]

Democratic Party[change | change source]

References[change | change source]

  1. "Voter Turnout in Presidential Elections". The American Presidency Project. UC Santa Barbara.