Beresford, South Dakota

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Beresford, South Dakota
City
A city street in Beresford
Location of Beresford in South Dakota
Coordinates: 43°4′51″N 96°46′34″W / 43.08083°N 96.77611°W / 43.08083; -96.77611Coordinates: 43°4′51″N 96°46′34″W / 43.08083°N 96.77611°W / 43.08083; -96.77611
Country United States
State South Dakota
Counties Union, Lincoln
Area
 • Total 1.78 sq mi (4.61 km2)
 • Land 1.78 sq mi (4.61 km2)
 • Water 0.00 sq mi (0.00 km2)
Elevation 1,499 ft (457 m)
Population (2010)[1]
 • Total 2,005
 • Density 1,126.4/sq mi (434.9/km2)
Time zone CST (UTC-6)
 • Summer (DST) CDT (UTC-5)

Beresford is a city in the southeastern part of the U.S. state of South Dakota. Most of the city is located in Union County, but a small part of it is in Lincoln County. Beresford became a city in 1884,[2] and 2,005 people lived there at the 2010 census.[1]

References[change | edit source]

Other websites[change | edit source]