Seymour, Connecticut

From Simple English Wikipedia, the free encyclopedia

Seymour is a town in New Haven County, Connecticut, United States. As of the 2020 census, 16,748 people lived there.[1]

References[change | change source]

  1. "Census - Geography Profile: Seymour town, New Haven County, Connecticut". United States Census Bureau. Retrieved December 21, 2021.

Other websites[change | change source]